The expression $8^{-2}$ can be simplified as follows:

$8^{-2} = \frac{1}{8^2}$

Since $8^2 = 64$, we get:

$8^{-2} = \frac{1}{64}$

So, $8^{-2} = \frac{1}{64}$.

Would you like further details or have any questions?

Here are 5 related questions to explore:

1. What is $5^{-3}$?
2. How would you simplify $(2^3)^{-2}$?
3. What is the decimal value of $8^{-2}$?
4. How do you calculate $x^{-n}$ for any base $x$ and exponent $n$?
5. What is the value of $(3 \times 4)^{-1}$?

Tip: Negative exponents represent the reciprocal of the base raised to the positive exponent.